280 var array_of_functions = [ first_function, second_function, third_function, forth_function ] and then when you want to execute a given function in the array:

Apr 17, 2017 · 54 This seems unnecessary since the Array() function documentation clearly states that the function returns a Variant type, but VBA is a strange place. If you declare an array variable (of …

I have a struct that contains a declaration like this one: void (*functions[256])(void) //Array of 256 functions without arguments and return value And in another function I want to define it, but...

Dec 14, 2014 · You pass a pointer to an array of 10 int *, but func expects an int** (which is expected to be a pointer to the first element of an array of (10, presumably) int* s).

Jun 7, 2014 · The short answer is, you are actually testing the sizeof a pointer rather than an array, because "the array is implicitly converted, or decays, into a pointer. The pointer, alas, doesn't store …

Jul 4, 2011 · If a parameter is declared as an array with a specified size, the corresponding argument in each function call should point into an object that has at least as many elements as the array.

Here is an example where I receive 2 bash arrays into a function, as well as additional arguments after them. This pattern can be continued indefinitely for any number of bash arrays and any number of …

The array declared in the calling sub has to be of undeclared length. The function that returns an array has to be of EXACTLY same type. Even if you declare the array in the sub as a Variant and the …

In C, an expression of type "N-element array of T " will be implicitly converted ("decay") to an expression of type "pointer to T ", except when the array expression is an operand of the sizeof or unary & …

Aug 13, 2010 · 140 C++ functions can't return C-style arrays by value. The closest thing is to return a pointer. Furthermore, an array type in the argument list is simply converted to a pointer.